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	<title>Comentários sobre: Atividade de química, sobre aluminio e alumina!</title>
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		<title>Por: okinawa</title>
		<link>http://www.professoronline.net/atividade-de-quimica-sobre-aluminio-e-alumina/comment-page-1/#comment-2495</link>
		<dc:creator><![CDATA[okinawa]]></dc:creator>
		<pubDate>Fri, 16 Dec 2016 22:59:11 +0000</pubDate>
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		<description><![CDATA[Massa molar do Al2O3 = 27 x 2 + 16 x 3 = 102 g/mol

Massa molar do CO2 = 12 + 16 x 2 = 44 g/mol

Note que a equação já está balanceada:

2 Al2O3 +3 C------------------------------&gt;3 CO2+4 Al

2 . 102 g de Al2O3 ----------------------&gt; 3 . 44 g de CO2
408 g de Al2O3 ----------------------------&gt; x g de CO2

2.102 . x = 3 . 44 .408

204 x = 53856

x = 53856 / 204

x = 264 g de CO2


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		<content:encoded><![CDATA[<p>Massa molar do Al2O3 = 27 x 2 + 16 x 3 = 102 g/mol</p>
<p>Massa molar do CO2 = 12 + 16 x 2 = 44 g/mol</p>
<p>Note que a equação já está balanceada:</p>
<p>2 Al2O3 +3 C&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&gt;3 CO2+4 Al</p>
<p>2 . 102 g de Al2O3 &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-&gt; 3 . 44 g de CO2<br />
408 g de Al2O3 &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-&gt; x g de CO2</p>
<p>2.102 . x = 3 . 44 .408</p>
<p>204 x = 53856</p>
<p>x = 53856 / 204</p>
<p>x = 264 g de CO2</p>
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