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	<title>Comentários sobre: Equação do 2 grau, Matematica</title>
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		<title>Por: Marco.Nakashima</title>
		<link>http://www.professoronline.net/equacao-do-2-grau-matematica/comment-page-1/#comment-1553</link>
		<dc:creator><![CDATA[Marco.Nakashima]]></dc:creator>
		<pubDate>Fri, 16 May 2014 04:30:03 +0000</pubDate>
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		<description><![CDATA[Propriedade distributiva: multiplicar todos os fatores dentro de cada parênteses: 
(x-a)*(x-b) = x^2 - bx - ax + ab

Encontrar raízes
a) 5x² + 7x = 3x² +2x
   2x² + 5x = 0
   x (2x + 5) = 0
x = 0 ou 
2x + 5 = 0     x = 5/2

b) (2x – 3).(x + 4) = 10
    2x² + 8x - 3x - 12 = 10
    2x² + 5x - 2 = 0

ax² + bx + c = 0 
x = (- b ± sqrt(b²-4ac))/ 2a

substituindo:

x = -5 ± sqrt(5² - 4.2.2) / 2.2
x = -2 ou x = -1/2 
 ]]></description>
		<content:encoded><![CDATA[<p>Propriedade distributiva: multiplicar todos os fatores dentro de cada parênteses:<br />
(x-a)*(x-b) = x^2 &#8211; bx &#8211; ax + ab</p>
<p>Encontrar raízes<br />
a) 5x² + 7x = 3x² +2x<br />
   2x² + 5x = 0<br />
   x (2x + 5) = 0<br />
x = 0 ou<br />
2x + 5 = 0     x = 5/2</p>
<p>b) (2x – 3).(x + 4) = 10<br />
    2x² + 8x &#8211; 3x &#8211; 12 = 10<br />
    2x² + 5x &#8211; 2 = 0</p>
<p>ax² + bx + c = 0<br />
x = (- b ± sqrt(b²-4ac))/ 2a</p>
<p>substituindo:</p>
<p>x = -5 ± sqrt(5² &#8211; 4.2.2) / 2.2<br />
x = -2 ou x = -1/2 </p>
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