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1) verifique se (0; 1; 1) é solução para os problemas
A)
X+Y+Z=2
X+Y-Z=0
2X+2Y+Z=3

B)
3X-Y-Z= -2
X-Y-Z=0
2X+Y-Z=0

C)
5X+3Y-3Z=0
4X+5Y-3Z=2
X+3Y+4Z=7

2)Assinale E para os sistemas que estão escalonados e ache o conjunto solução deles:
A)
2X+Y+Z=4
3Y+Z=5
Z=1

B)
2X+Y=5
X+Y=2

C)
3X+2Y+3Z+T=1
2Z-1=0

D)
X+Y=3
X-Y=7
2Y+X=1

E)
X+Y+Z=3
X+T=4
Y=5

F)
2X+Y+Z=1
3Y+Z=4
2Z=0

3) Escalone, classifique e resolva se for possível e determinado os seguintes sistemas lineares:

A)
X+Y+Z=1
2X+Y-3Z=4
3X+2Y-2Z=5

B)
2X+Y=1
X-Y= -1
X+2Y=0

C)
X+2Y-3Z=4
2X+Y-Z=1

D)
X+Y+Z=4
X-Y-2Y=1
3X+2Y-Z=2

E)
X+Y=0
2X-Y=0

F)
X+Y+Z=0
X-Y-2Z=0
2X-Y3Z=0
4)(PUC-RS) Para que o sistema: X+Y-Z=1 é correto afirma que
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A) 0.2
B)0.25
C)0.33
D)0.8
E)1.25

5)(UFAM) Dado o sistema x+y-z=1 é correto afirmar que:
x+y+z=1

A- Tem uma solução com z=1

B- Não tem solução

C- Tem exatamente três soluções

D- Tem solução única X=0, Y=1 e Z=0

E- Tem uma infinidade de soluções

em: Matemática Perguntado por: 1231231212 [4 ]

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