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	<title>Comentários sobre: Movimento Obliquo Uma pedra roda pelo telhado de uma casa</title>
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		<title>Por: Marco.Nakashima</title>
		<link>http://www.professoronline.net/movimento-obliquo-uma-pedra-roda-pelo-telhado-de-uma-casa/comment-page-1/#comment-2210</link>
		<dc:creator><![CDATA[Marco.Nakashima]]></dc:creator>
		<pubDate>Fri, 27 Nov 2015 01:01:35 +0000</pubDate>
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		<description><![CDATA[Dados:
Y = 6m
V0 = 4m/s
g = 10m/s2
A = 20o
Vx = V0.cos(20) = 3,76m/s
Vy = V0.sen(20) = 1,36m/s

a)S = S0 + Vy0t + g/2t2
6 = 1,36t + (10/2)t2
Resolvendo a equação de 2o grau, 

t = 0,94s

b) X = X0 + Vx t
X = 3,76 * 0,94 = 3,54m

c)Vx = 3,76m/s (Mov. Retilíneo Uniforme)
Vy = V0y + gt
Vy = 1,36 + 10(0,94) = 10,76m/s

tg(A&#039;) = Vx/Vy 3,76/10,76

arctg(3,76/10,76) = A = 19,26o 
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		<content:encoded><![CDATA[<p>Dados:<br />
Y = 6m<br />
V0 = 4m/s<br />
g = 10m/s2<br />
A = 20o<br />
Vx = V0.cos(20) = 3,76m/s<br />
Vy = V0.sen(20) = 1,36m/s</p>
<p>a)S = S0 + Vy0t + g/2t2<br />
6 = 1,36t + (10/2)t2<br />
Resolvendo a equação de 2o grau, </p>
<p>t = 0,94s</p>
<p>b) X = X0 + Vx t<br />
X = 3,76 * 0,94 = 3,54m</p>
<p>c)Vx = 3,76m/s (Mov. Retilíneo Uniforme)<br />
Vy = V0y + gt<br />
Vy = 1,36 + 10(0,94) = 10,76m/s</p>
<p>tg(A&#8217;) = Vx/Vy 3,76/10,76</p>
<p>arctg(3,76/10,76) = A = 19,26o </p>
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