<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:wfw="http://wellformedweb.org/CommentAPI/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
	>

<channel>
	<title>Professores Online &#187; HenriqueBorges</title>
	<atom:link href="http://www.professoronline.net/profile/henriqueborges/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.professoronline.net</link>
	<description></description>
	<lastBuildDate>Thu, 13 Jun 2024 14:08:46 +0000</lastBuildDate>
	<language>pt-BR</language>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>https://wordpress.org/?v=4.1.41</generator>
	<item>
		<title>Cálculo de Limite com x tendendo a 0</title>
		<link>http://www.professoronline.net/calculo-de-limite-com-x-tendendo-a-0/</link>
		<comments>http://www.professoronline.net/calculo-de-limite-com-x-tendendo-a-0/#comments</comments>
		<pubDate>Sat, 22 Sep 2012 21:42:01 +0000</pubDate>
		<dc:creator><![CDATA[HenriqueBorges]]></dc:creator>
				<category><![CDATA[Matemática]]></category>
		<category><![CDATA[0]]></category>
		<category><![CDATA[a]]></category>
		<category><![CDATA[cálculo]]></category>
		<category><![CDATA[com]]></category>
		<category><![CDATA[de]]></category>
		<category><![CDATA[limite]]></category>
		<category><![CDATA[tendendo]]></category>
		<category><![CDATA[x]]></category>

		<guid isPermaLink="false"></guid>
		<description><![CDATA[Estou com duvida quanto a resolução desse cálculo, gostaria pudessem me ajudar: lim (4+x)^2-16/x x?0 &#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.]]></description>
				<content:encoded><![CDATA[<p>Estou com duvida quanto a resolução desse cálculo, gostaria pudessem me ajudar:<br />
lim  (4+x)^2-16/x<br />
x?0</p>
<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.</p>
]]></content:encoded>
			<wfw:commentRss>http://www.professoronline.net/calculo-de-limite-com-x-tendendo-a-0/feed/</wfw:commentRss>
		<slash:comments>0</slash:comments>
		</item>
	</channel>
</rss>
