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	<title>Professores Online &#187; IngridGusmao</title>
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		<title>Pq E (3d 8) e J (4f 3) não formam composto covalente E2J3?</title>
		<link>http://www.professoronline.net/pq-e-3d-8-e-j-4f-3-nao-formam-composto-covalente-e2j3/</link>
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		<pubDate>Thu, 16 May 2013 20:48:48 +0000</pubDate>
		<dc:creator><![CDATA[IngridGusmao]]></dc:creator>
				<category><![CDATA[Química]]></category>
		<category><![CDATA[3]]></category>
		<category><![CDATA[3d]]></category>
		<category><![CDATA[4f]]></category>
		<category><![CDATA[8]]></category>
		<category><![CDATA[composto]]></category>
		<category><![CDATA[covalente]]></category>
		<category><![CDATA[e]]></category>
		<category><![CDATA[e2j3]]></category>
		<category><![CDATA[formam]]></category>
		<category><![CDATA[j]]></category>
		<category><![CDATA[nao]]></category>
		<category><![CDATA[pq]]></category>

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		<description><![CDATA[Os átomos: E, G, J, M apresentam seus respectivos subníveis mais energéticos, que são: E &#8211; 3d8 G &#8211; 3p4 J &#8211; 4f3 M &#8211; 4s1 Com relação a estes dados assinale a alternativa correta: a) G e M formam composto iônico, cuja fórmula é G2M b) o íon J+3 possui como subnível mais energético [&#8230;]]]></description>
				<content:encoded><![CDATA[<p>Os átomos: E, G, J, M apresentam seus respectivos subníveis mais energéticos, que são:</p>
<p>E &#8211; 3d8<br />
G &#8211; 3p4<br />
J &#8211; 4f3<br />
M &#8211; 4s1</p>
<p>Com relação a estes dados assinale a alternativa correta:</p>
<p>a) G e M formam composto iônico, cuja fórmula é G2M<br />
b) o íon J+3 possui como subnível mais energético o 6s2<br />
c) E e J formam composto covalente de fórmula química E2J3<br />
d) o elétron do átomo E, com os números quânticos: n = 4; ? = 0; m? = 0 ms= -1/2, pertence ao subnível 4s<br />
_____________________________________</p>
<p>MINHA DÚVIDA É:</p>
<p>Eu sei que a resposta é letra \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\&#8221;D\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\&#8221;, mas gostaria de saber o porquê da letra \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\&#8221;C\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\&#8221; estar errada</p>
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