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	<title>Comentários sobre: Teorema Binomial-Expansão Polinomial</title>
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		<title>Por: ronaldomoreira</title>
		<link>http://www.professoronline.net/teorema-binomial-expansao-polinomial/comment-page-1/#comment-2157</link>
		<dc:creator><![CDATA[ronaldomoreira]]></dc:creator>
		<pubDate>Sun, 11 Oct 2015 17:57:17 +0000</pubDate>
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		<description><![CDATA[a^3 + 6a^2b + 12ab^2 + 8b^3 + 8a^3 - 12a^2b + 6ab^2 - b^3 = - 1 + 8a^3 

(a+2b)^3 + (2a-b)^3 = (-1)^3 + (2a)^3 

a + 2b = - 1 
2a - b = 2a 

b = 0 
a = - 1 

a+b = - 1 

a+2b = 2a 
2a-b = -1 

- a+ 2b = 0 
4a - 2b = - 2 
-------------------- 
3a = - 2 
a = - 2/3 
-2/3 = 2b 
b = - 1/3 

a+b = - 1]]></description>
		<content:encoded><![CDATA[<p>a^3 + 6a^2b + 12ab^2 + 8b^3 + 8a^3 &#8211; 12a^2b + 6ab^2 &#8211; b^3 = &#8211; 1 + 8a^3 </p>
<p>(a+2b)^3 + (2a-b)^3 = (-1)^3 + (2a)^3 </p>
<p>a + 2b = &#8211; 1<br />
2a &#8211; b = 2a </p>
<p>b = 0<br />
a = &#8211; 1 </p>
<p>a+b = &#8211; 1 </p>
<p>a+2b = 2a<br />
2a-b = -1 </p>
<p>&#8211; a+ 2b = 0<br />
4a &#8211; 2b = &#8211; 2<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<br />
3a = &#8211; 2<br />
a = &#8211; 2/3<br />
-2/3 = 2b<br />
b = &#8211; 1/3 </p>
<p>a+b = &#8211; 1</p>
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