http://www.professoronline.net/trabalho-na-qual-preciso-entregar-ele-hoje/ Tue, 09 Nov 2021 23:24:03 +0000 hourly 1 https://wordpress.org/?v=4.1.41 http://www.professoronline.net/trabalho-na-qual-preciso-entregar-ele-hoje/comment-page-1/#comment-697 Thu, 27 Dec 2012 17:27:35 +0000 #comment-697 C = 12 x 2 = 24
O = 16 x 2 = 32
H = 1 x 4 = 4
M = 24 + 32 + 4 = 60 g/mol
1 mol = 6,0 . 10²³ moléculas
52 g —- 1 Litro
x ——– 0,005 Litro
x = (52 . 0,005)/1 = 0,26 g = 2,6.10^1 g
1 mol —- 60 g/mol —– 6.10²³ moléculas
2,6.10^1 g —— y
y = (2,6.10^1 x 6.10²³)/60g/mol
y = (15,6.10^24)/60 = 1,56.10^23/60
y = 0,026.10^23 = 2,6.10².10²³ = 2,6.10^25 moléculas em 5 ml

]]>