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	<title>Comentários sobre: Calculo passo a passo divisor de tensao</title>
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		<title>Por: dri2604</title>
		<link>https://www.professoronline.net/calculo-passo-a-passo-divisor-de-tensao/comment-page-1/#comment-1677</link>
		<dc:creator><![CDATA[dri2604]]></dc:creator>
		<pubDate>Mon, 28 Jul 2014 21:42:33 +0000</pubDate>
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		<description><![CDATA[5=r2/10000+r2.25
5/25=r2/10000+r2
50000+5r2=25r2
50000=20r2
r2=2500
ou 2,5k ohm]]></description>
		<content:encoded><![CDATA[<p>5=r2/10000+r2.25<br />
5/25=r2/10000+r2<br />
50000+5r2=25r2<br />
50000=20r2<br />
r2=2500<br />
ou 2,5k ohm</p>
]]></content:encoded>
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		<title>Por: BILL</title>
		<link>https://www.professoronline.net/calculo-passo-a-passo-divisor-de-tensao/comment-page-1/#comment-1668</link>
		<dc:creator><![CDATA[BILL]]></dc:creator>
		<pubDate>Mon, 28 Jul 2014 19:29:02 +0000</pubDate>
		<guid isPermaLink="false">#comment-1668</guid>
		<description><![CDATA[Sendo divisor de tensão por 5,
onde V2 a tensão de saída e V a tensão de entrada, temos:
V2=Vx(1/5). 
Para V2=5 volts, temos que:
5=Vx(1/5)
V=25 volts
 E que:
V2 = [R2 / (R1+R2)] x V. 
Logo:
5=[R2/(10000+R2)] x 25.
Assim:
1=[R2/(10000+R2)] x 5
5R2=10000+R2 
4R2=10000
R2=2,5K?
]]></description>
		<content:encoded><![CDATA[<p>Sendo divisor de tensão por 5,<br />
onde V2 a tensão de saída e V a tensão de entrada, temos:<br />
V2=Vx(1/5).<br />
Para V2=5 volts, temos que:<br />
5=Vx(1/5)<br />
V=25 volts<br />
 E que:<br />
V2 = [R2 / (R1+R2)] x V.<br />
Logo:<br />
5=[R2/(10000+R2)] x 25.<br />
Assim:<br />
1=[R2/(10000+R2)] x 5<br />
5R2=10000+R2<br />
4R2=10000<br />
R2=2,5K?</p>
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