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	<title>Comentários sobre: Equação de 2º grau completa</title>
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		<title>Por: TG...7</title>
		<link>https://www.professoronline.net/equacao-de-2%c2%ba-grau-completa/comment-page-1/#comment-558</link>
		<dc:creator><![CDATA[TG...7]]></dc:creator>
		<pubDate>Mon, 15 Oct 2012 14:15:52 +0000</pubDate>
		<guid isPermaLink="false">#comment-558</guid>
		<description><![CDATA[(x-2)^2-x=0
(x-2)*(x-2)-x=0
x^2-4x+2-x=0
x^2-5x+2=0
a=1;b=-5;e c=+2
x=(-b±?(b^2-4ac))/2a
x=(-(-5)±?(?(-5)?^2-4*1*) 2)/(2*1)
x=(5+?33)/2     e 
x=(5-?33)/2
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		<content:encoded><![CDATA[<p>(x-2)^2-x=0<br />
(x-2)*(x-2)-x=0<br />
x^2-4x+2-x=0<br />
x^2-5x+2=0<br />
a=1;b=-5;e c=+2<br />
x=(-b±?(b^2-4ac))/2a<br />
x=(-(-5)±?(?(-5)?^2-4*1*) 2)/(2*1)<br />
x=(5+?33)/2     e<br />
x=(5-?33)/2</p>
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	<item>
		<title>Por: AlinedaSilva</title>
		<link>https://www.professoronline.net/equacao-de-2%c2%ba-grau-completa/comment-page-1/#comment-554</link>
		<dc:creator><![CDATA[AlinedaSilva]]></dc:creator>
		<pubDate>Mon, 08 Oct 2012 02:06:30 +0000</pubDate>
		<guid isPermaLink="false">#comment-554</guid>
		<description><![CDATA[primeiro você deve resolver a potenciação que está dentro do parenteses. 

(x-2)² + x = 0
x²-4+x=o
x²+x-4=0]]></description>
		<content:encoded><![CDATA[<p>primeiro você deve resolver a potenciação que está dentro do parenteses. </p>
<p>(x-2)² + x = 0<br />
x²-4+x=o<br />
x²+x-4=0</p>
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