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	<title>Comentários sobre: Função Horária S= -15 -2t+t2(no SI)</title>
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		<title>Por: Marco.Nakashima</title>
		<link>https://www.professoronline.net/funcao-horaria-s-15-2tt2no-si/comment-page-1/#comment-952</link>
		<dc:creator><![CDATA[Marco.Nakashima]]></dc:creator>
		<pubDate>Thu, 25 Apr 2013 01:58:33 +0000</pubDate>
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		<description><![CDATA[Boa Noite! 
S(t) = -15-2t+t^2

a) MUV (por que tem t^2)

b) S(0) = -15 (só igualar t = 0)

c) v(t) = dS/dt = 2t-2

d) S(t) = 0
t = [2 +/- sqrt((2^2)-4*1*(-15))]/2*1
t = 5s ou t = -3s (não existe tempo negativo)

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		<content:encoded><![CDATA[<p>Boa Noite!<br />
S(t) = -15-2t+t^2</p>
<p>a) MUV (por que tem t^2)</p>
<p>b) S(0) = -15 (só igualar t = 0)</p>
<p>c) v(t) = dS/dt = 2t-2</p>
<p>d) S(t) = 0<br />
t = [2 +/- sqrt((2^2)-4*1*(-15))]/2*1<br />
t = 5s ou t = -3s (não existe tempo negativo)</p>
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