<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	
	>
<channel>
	<title>Comentários sobre: Olá,tenho uma pergunta para ser resolvida.</title>
	<atom:link href="https://www.professoronline.net/olatenho-uma-pergunta-para-ser-resolvida/feed/" rel="self" type="application/rss+xml" />
	<link>https://www.professoronline.net/olatenho-uma-pergunta-para-ser-resolvida/</link>
	<description></description>
	<lastBuildDate>Tue, 09 Nov 2021 23:24:03 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>https://wordpress.org/?v=4.1.41</generator>
	<item>
		<title>Por: GabrielB</title>
		<link>https://www.professoronline.net/olatenho-uma-pergunta-para-ser-resolvida/comment-page-1/#comment-1318</link>
		<dc:creator><![CDATA[GabrielB]]></dc:creator>
		<pubDate>Fri, 20 Dec 2013 04:12:47 +0000</pubDate>
		<guid isPermaLink="false">#comment-1318</guid>
		<description><![CDATA[A equação geral da circunferencia é:

(X-xc)^2 + (y-yc)^2 = r^2

Onde:xc,yc:coordenadas do centro

Resposta: (x+3)^2 + (y+11)^2 = 100

Ou expandindo: x^2+y^2+6x+22y+30=0]]></description>
		<content:encoded><![CDATA[<p>A equação geral da circunferencia é:</p>
<p>(X-xc)^2 + (y-yc)^2 = r^2</p>
<p>Onde:xc,yc:coordenadas do centro</p>
<p>Resposta: (x+3)^2 + (y+11)^2 = 100</p>
<p>Ou expandindo: x^2+y^2+6x+22y+30=0</p>
]]></content:encoded>
	</item>
	<item>
		<title>Por: Brunoheld</title>
		<link>https://www.professoronline.net/olatenho-uma-pergunta-para-ser-resolvida/comment-page-1/#comment-1317</link>
		<dc:creator><![CDATA[Brunoheld]]></dc:creator>
		<pubDate>Thu, 19 Dec 2013 23:31:23 +0000</pubDate>
		<guid isPermaLink="false">#comment-1317</guid>
		<description><![CDATA[Resposta #1
Caso queria obter a area essa é a equação:
A=PI*(R*R)]]></description>
		<content:encoded><![CDATA[<p>Resposta #1<br />
Caso queria obter a area essa é a equação:<br />
A=PI*(R*R)</p>
]]></content:encoded>
	</item>
	<item>
		<title>Por: Brunoheld</title>
		<link>https://www.professoronline.net/olatenho-uma-pergunta-para-ser-resolvida/comment-page-1/#comment-1314</link>
		<dc:creator><![CDATA[Brunoheld]]></dc:creator>
		<pubDate>Thu, 19 Dec 2013 22:13:49 +0000</pubDate>
		<guid isPermaLink="false">#comment-1314</guid>
		<description><![CDATA[
Caso queria obter a area essa é a equação:

   A=PI*(R*R)]]></description>
		<content:encoded><![CDATA[<p>Caso queria obter a area essa é a equação:</p>
<p>   A=PI*(R*R)</p>
]]></content:encoded>
	</item>
</channel>
</rss>
